What is (1/10 mn)(4/9 mn)(9/4 mn^3) ?

The solution to (1/10 mn)(4/9 mn)(9/4 mn^3) is (m^3n^5)/(10)

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simplify (1/10 mn)(4/9 mn)(9/4 mn^3)

simplify

(\frac{1}{10} mn) (\frac{4}{9} mn) (\frac{9}{4} m n^{3})

\frac{m ^{3} n ^{5}}{10}

Solution steps

(\frac{1}{10} mn) (\frac{4}{9} mn) (\frac{9}{4} m n^{3})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

mmm = m^{1 + 1 + 1}

= \frac{1}{10} n \frac{4}{9} n \frac{9}{4} m^{1 + 1 + 1} n^{3}

Add the numbers:

1 + 1 + 1 = 3

= \frac{1}{10} n \frac{4}{9} n \frac{9}{4} m^{3} n^{3}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

nn n^{3} = n^{1 + 1 + 3}

= \frac{1}{10} \cdot \frac{4}{9} \cdot \frac{9}{4} m^{3} n^{1 + 1 + 3}

Add the numbers:

1 + 1 + 3 = 5

= \frac{1}{10} \cdot \frac{4}{9} \cdot \frac{9}{4} m^{3} n^{5}

Multiply fractions:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{1 \cdot 4 \cdot 9 m ^{3} n ^{5}}{10 \cdot 9 \cdot 4}

Cancel the common factor:

4

= \frac{1 \cdot 9 m ^{3} n ^{5}}{10 \cdot 9}

Cancel the common factor:

9

= \frac{1 \cdot m ^{3} n ^{5}}{10}

Multiply:

1 \cdot m^{3} = m^{3}

= \frac{m ^{3} n ^{5}}{10}

2 w^{2} (4 w h) (2 w h)

2.11882 x 1 0^{- 27}

5.6 (1 0^{- 10})

4 - 15 \cdot 4 + 15

What is (1/10 mn)(4/9 mn)(9/4 mn^3) ?
The solution to (1/10 mn)(4/9 mn)(9/4 mn^3) is (m^3n^5)/(10)