What is (7*10^a)*(9*10^b) ?

The solution to (7*10^a)*(9*10^b) is 63*10^{a+b}

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simplify (710^a)(9*10^b)

simplify

(7 \cdot 1 0^{a}) \cdot (9 \cdot 1 0^{b})

63 \cdot 1 0^{a + b}

Solution steps

(7 \cdot 1 0^{a}) (9 \cdot 1 0^{b})

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

1 0^{a} \cdot 1 0^{b} = 1 0^{a + b}

= 7 \cdot 9 \cdot 1 0^{a + b}

Multiply the numbers:

7 \cdot 9 = 63

= 63 \cdot 1 0^{a + b}

- x \cdot x + h

- 119.6 e^{- 0.025 \cdot 1}

2 \cdot 0.6 \cdot 0. 4^{2} \cdot 75 \cdot e^{- 0.3}

(- x + 1) e^{- x}

e^{- x} (C^{1} cos (2 x) + C^{2} sin (2 x))