What is M^1(1,1,1)M^2(2,-1,0)M^3(-1,2,-2) ?

The solution to M^1(1,1,1)M^2(2,-1,0)M^3(-1,2,-2) is (1*1*1,,)(2,-1*0,)(-1*2,,-2)M^6

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simplify M^1(1,1,1)M^2(2,-1,0)M^3(-1,2,-2)

simplify

M^{1} (1, 1, 1) M^{2} (2, - 1, 0) M^{3} (- 1, 2, - 2)

(1 \cdot 1 \cdot 1,,) (2, - 1 \cdot 0,) (- 1 \cdot 2,, - 2) M^{6}

Solution steps

M^{1} (1, 1, 1) M^{2} (2, - 1, 0) M^{3} (- 1, 2, - 2)

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

M^{1} M^{2} M^{3} = M^{1 + 2 + 3}

= (1, 1, 1) (2, - 1, 0) M^{1 + 2 + 3} (- 1, 2, - 2)

Add the numbers:

1 + 2 + 3 = 6

= (1, 1, 1) (2, - 1, 0) M^{6} (- 1, 2, - 2)

1000 \cdot 4.27 \cdot 1 0^{- 4} \cdot 97.994

4 π \cdot 1 0^{- 7} \cdot 2 \cdot \frac{1}{2 π \cdot 0.014}

(e^{- y})^{n - 1}

\frac{1}{2} ln (x) e^{- x}

What is M^1(1,1,1)M^2(2,-1,0)M^3(-1,2,-2) ?
The solution to M^1(1,1,1)M^2(2,-1,0)M^3(-1,2,-2) is (1*1*1,,)(2,-1*0,)(-1*2,,-2)M^6