What is (6x^3y)/(x^2)*(3x^2y)/(8x^3) ?

The solution to (6x^3y)/(x^2)*(3x^2y)/(8x^3) is (9y^2)/4

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simplify (6x^3y)/(x^2)*(3x^2y)/(8x^3)

simplify

\frac{6 x ^{3} y}{x ^{2}} \cdot \frac{3 x ^{2} y}{8 x ^{3}}

\frac{9 y ^{2}}{4}

Solution steps

\frac{6 x ^{3} y}{x ^{2}} \cdot \frac{3 x ^{2} y}{8 x ^{3}}

Cancel

\frac{6 x ^{3} y}{x ^{2}} : 6 x y

= 6 x y \frac{3 x ^{2} y}{8 x ^{3}}

Cancel

\frac{3 x ^{2} y}{8 x ^{3}} : \frac{3 y}{8 x}

= 6 x y \frac{3 y}{8 x}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{6 x y \cdot 3 y}{8 x}

Apply exponent rule:

aa = a^{2}

yy = y^{2}

= \frac{6 x y ^{2} \cdot 3}{8 x}

Cancel the common factor:

x

= \frac{6 y ^{2} \cdot 3}{8}

Factor the number:

6 = 2 \cdot 3

= \frac{2 \cdot 3 y ^{2} \cdot 3}{8}

Factor the number:

8 = 2 \cdot 4

= \frac{2 \cdot 3 y ^{2} \cdot 3}{2 \cdot 4}

Cancel the common factor:

2

= \frac{3 y ^{2} \cdot 3}{4}

Multiply the numbers:

3 \cdot 3 = 9

= \frac{9 y ^{2}}{4}

63 x^{2} - 129 x + 36

- 8 x + 4 > - 3 x - 31

2 x + 4 < 6 x + 1

(p - 1)^{2} = 6

- 8 u - 18 = - 2 u - 12

What is (6x^3y)/(x^2)*(3x^2y)/(8x^3) ?
The solution to (6x^3y)/(x^2)*(3x^2y)/(8x^3) is (9y^2)/4