What is 1+2log_{10}(x)-log_{10}(y) ?

The solution to 1+2log_{10}(x)-log_{10}(y) is 1+log_{10}((x^2)/y)

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simplify 1+2log_{10}(x)-log_{10}(y)

simplify

1 + 2 lo g_{10} (x) - lo g_{10} (y)

1 + lo g_{10} (\frac{x ^{2}}{y})

Solution steps

1 + 2 lo g_{10} (x) - lo g_{10} (y)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (x) = lo g_{10} (x^{2})

= 1 + lo g_{10} (x^{2}) - lo g_{10} (y)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (x^{2}) - lo g_{10} (y) = lo g_{10} (\frac{x ^{2}}{y})

= 1 + lo g_{10} (\frac{x ^{2}}{y})

- lo g_{10} (3.3 \cdot 1 0^{- 11})

ln (5 x) + ln (2 y^{3}) - ln (x^{2} y)

3 lo g_{b} (x + 2) - lo g_{b} (x)

ln (\frac{1}{k})

What is 1+2log_{10}(x)-log_{10}(y) ?
The solution to 1+2log_{10}(x)-log_{10}(y) is 1+log_{10}((x^2)/y)