What are the solutions to the equation x^2+13x+7=0 ?

The solutions to the equation x^2+13x+7=0 are x=(-13+sqrt(141))/2 ,x=(-13-sqrt(141))/2

Find the zeros of x^2+13x+7=0

The zeros of x^2+13x+7=0 are x=(-13+sqrt(141))/2 ,x=(-13-sqrt(141))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 13 x + 7 = 0

x = \frac{- 13 + 141}{2}, x = \frac{- 13 - 141}{2}

Decimal Notation

x = - 0.56282 \dots, x = - 12.43717 \dots

Solution steps

x^{2} + 13 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 7 = 141

x_{1, 2} = \frac{- 13 \pm 141}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 13 + 141}{2 \cdot 1}, x_{2} = \frac{- 13 - 141}{2 \cdot 1}

x = \frac{- 13 + 141}{2 \cdot 1} : \frac{- 13 + 141}{2}

x = \frac{- 13 - 141}{2 \cdot 1} : \frac{- 13 - 141}{2}

The solutions to the quadratic equation are:

x = \frac{- 13 + 141}{2}, x = \frac{- 13 - 141}{2}

y^{2} + x^{5} y^{4}

2 x^{2} - 11 x - 6

5 - 6 x = 7 x + 5

3 (4 x - 2) - 5 x = 6 - 7 (- x - 2)

x^{2} - 16 x - 36

What are the solutions to the equation x^2+13x+7=0 ?
The solutions to the equation x^2+13x+7=0 are x=(-13+sqrt(141))/2 ,x=(-13-sqrt(141))/2
Find the zeros of x^2+13x+7=0
The zeros of x^2+13x+7=0 are x=(-13+sqrt(141))/2 ,x=(-13-sqrt(141))/2