What is e^{-sqrt(2)}-ln(3/7) ?

The solution to e^{-sqrt(2)}-ln(3/7) is 1/(e^{sqrt(2))}-ln(3)+ln(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify e^{-sqrt(2)}-ln(3/7)

simplify

e^{- 2} - ln (\frac{3}{7})

\frac{1}{e ^{2}} - ln (3) + ln (7)

Decimal Notation

1.09041 \dots

Solution steps

e^{- 2} - ln (\frac{3}{7})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{3}{7}) = ln (3) - ln (7)

= e^{- 2} - (ln (3) - ln (7))

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{2}} - (ln (3) - ln (7))

- (ln (3) - ln (7)) : - ln (3) + ln (7)

= \frac{1}{e ^{2}} - ln (3) + ln (7)

ln (\frac{x y ^{2}}{z ^{4}})

- lo g_{10} (1.4 \cdot 1 0^{- 9})

- ln (2) + 2 (ln (7) - ln (6))

2 - x + 3 ln (x + y) - 3 ln (x - y)

ln (\frac{- x}{y - 2 x})

What is e^{-sqrt(2)}-ln(3/7) ?
The solution to e^{-sqrt(2)}-ln(3/7) is 1/(e^{sqrt(2))}-ln(3)+ln(7)