What is ln((153.5)/(100))+(1/2*0.4^2-0.02)*4 ?

The solution to ln((153.5)/(100))+(1/2*0.4^2-0.02)*4 is ln(153.5)-2ln(10)+4((0.16)/2-0.02)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln((153.5)/(100))+(1/20.4^2-0.02)4

simplify

ln (\frac{153.5}{100}) + (\frac{1}{2} \cdot 0. 4^{2} - 0.02) \cdot 4

ln (153.5) - 2 ln (10) + 4 (\frac{0.16}{2} - 0.02)

Decimal Notation

0.66853 \dots

Solution steps

ln (\frac{153.5}{100}) + (\frac{1}{2} \cdot 0. 4^{2} - 0.02) \cdot 4

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{153.5}{100}) = ln (153.5) - ln (100)

= ln (153.5) - ln (100) + 4 (0. 4^{2} \cdot \frac{1}{2} - 0.02)

\frac{1}{2} \cdot 0. 4^{2} = \frac{0.16}{2}

= ln (153.5) - ln (100) + 4 (\frac{0.16}{2} - 0.02)

ln (100) = 2 ln (10)

= ln (153.5) - 2 ln (10) + 4 (\frac{0.16}{2} - 0.02)

\frac{1}{2} ln (2 x)

- lo g_{10} (3.75 \cdot 1 0^{2})

3 ln (x) - 2 ln (c)

lo g_{10} (\frac{1}{e})

3 lo g_{10} (x) + 4 lo g_{10} (x - 2)

What is ln((153.5)/(100))+(1/2*0.4^2-0.02)*4 ?
The solution to ln((153.5)/(100))+(1/2*0.4^2-0.02)*4 is ln(153.5)-2ln(10)+4((0.16)/2-0.02)