What is join-(2ln(10x+5y-2)}{25}+\frac{2x+y)/5 ?

The solution to join-(2ln(10x+5y-2)}{25}+\frac{2x+y)/5 is -(ln((10x+5y-2)^2)}{25}+\frac{2x+y)/5

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join-(2ln(10x+5y-2)}{25}+\frac{2x+y)/5

join

- \frac{2 ln ( 10 x + 5 y - 2 )}{25} + \frac{2 x + y}{5}

- \frac{ln ( ( 10 x + 5 y - 2 ) ^{2} )}{25} + \frac{2 x + y}{5}

Solution steps

- \frac{2 ln ( 10 x + 5 y - 2 )}{25} + \frac{2 x + y}{5}

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 ln (10 x + 5 y - 2) = ln ((10 x + 5 y - 2)^{2})

= - \frac{ln ( ( 10 x + 5 y - 2 ) ^{2} )}{25} + \frac{2 x + y}{5}

ln (6) + ln (3)

ln (4) - ln (\frac{1}{4})

- [\frac{3}{8} lo g_{2} (\frac{3}{8}) + \frac{5}{8} lo g_{2} (\frac{5}{8})]

ln (\frac{( 1 + x ) ^{6} \cdot x}{( 1 + x ) ^{6} - 1})

ln (x^{2} + 2 x) - 2 ln (x)

What is join-(2ln(10x+5y-2)}{25}+\frac{2x+y)/5 ?
The solution to join-(2ln(10x+5y-2)}{25}+\frac{2x+y)/5 is -(ln((10x+5y-2)^2)}{25}+\frac{2x+y)/5