What is ln((x+y-1)(x+y^2-3)) ?

The solution to ln((x+y-1)(x+y^2-3)) is ln(x+y-1)+ln(x+y^2-3)

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simplify ln((x+y-1)(x+y^2-3))

simplify

ln ((x + y - 1) (x + y^{2} - 3))

ln (x + y - 1) + ln (x + y^{2} - 3)

Solution steps

ln ((x + y - 1) (x + y^{2} - 3))

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln ((x + y - 1) (x + y^{2} - 3)) = ln (x + y - 1) + ln (x + y^{2} - 3)

= ln (x + y - 1) + ln (x + y^{2} - 3)

ln (\frac{( x ^{8} )}{x - 4})

ln (4) - 2 ln (x)

ln (8 x) - 2 ln (2 x) + 3 ln (2 x^{2})

\frac{2}{7} \cdot ln ∣ 65 - 6 ∣ + \frac{5}{7} \cdot ln ∣ 65 + 1 ∣

5 \cdot lo g_{10} (x) - 3 \cdot lo g_{10} (y)

What is ln((x+y-1)(x+y^2-3)) ?
The solution to ln((x+y-1)(x+y^2-3)) is ln(x+y-1)+ln(x+y^2-3)