What are the solutions to the equation x^2+3x-3/4 =0 ?

The solutions to the equation x^2+3x-3/4 =0 are x=(-3+2sqrt(3))/2 ,x=-(3+2sqrt(3))/2

Find the zeros of x^2+3x-3/4 =0

The zeros of x^2+3x-3/4 =0 are x=(-3+2sqrt(3))/2 ,x=-(3+2sqrt(3))/2

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x^{2} + 3 x - \frac{3}{4} = 0

x = \frac{- 3 + 2 3}{2}, x = - \frac{3 + 2 3}{2}

Decimal Notation

x = 0.23205 \dots, x = - 3.23205 \dots

Solution steps

x^{2} + 3 x - \frac{3}{4} = 0

Multiply both sides by

4

4 x^{2} + 12 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 3) = 83

x_{1, 2} = \frac{- 12 \pm 8 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 8 3}{2 \cdot 4}, x_{2} = \frac{- 12 - 8 3}{2 \cdot 4}

x = \frac{- 12 + 8 3}{2 \cdot 4} : \frac{- 3 + 2 3}{2}

x = \frac{- 12 - 8 3}{2 \cdot 4} : - \frac{3 + 2 3}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 2 3}{2}, x = - \frac{3 + 2 3}{2}

\frac{( x ^{3} e ^{- \frac{1}{y ^{3}}} + 5 y ^{5} ) d}{d x}

3 x^{2} - 4 x

\frac{- 6}{3} - \frac{4}{2 ( - 6 )}

2 x - 5 \leq 3

3 x^{2} - 4 x = - 7

What are the solutions to the equation x^2+3x-3/4 =0 ?
The solutions to the equation x^2+3x-3/4 =0 are x=(-3+2sqrt(3))/2 ,x=-(3+2sqrt(3))/2
Find the zeros of x^2+3x-3/4 =0
The zeros of x^2+3x-3/4 =0 are x=(-3+2sqrt(3))/2 ,x=-(3+2sqrt(3))/2