What is 4log_{b}(v)+3log_{b}(q) ?

The solution to 4log_{b}(v)+3log_{b}(q) is log_{b}(v^4q^3)

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simplify 4log_{b}(v)+3log_{b}(q)

simplify

4 lo g_{b} (v) + 3 lo g_{b} (q)

lo g_{b} (v^{4} q^{3})

Solution steps

4 lo g_{b} (v) + 3 lo g_{b} (q)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{b} (v) = lo g_{b} (v^{4})

= lo g_{b} (v^{4}) + 3 lo g_{b} (q)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 lo g_{b} (q) = lo g_{b} (q^{3})

= lo g_{b} (v^{4}) + lo g_{b} (q^{3})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{b} (v^{4}) + lo g_{b} (q^{3}) = lo g_{b} (v^{4} q^{3})

= lo g_{b} (v^{4} q^{3})

ln (\frac{6}{3.1 4 ^{2}})

ln ∣ z + 4 ∣ + 6 (\frac{1}{5} ln ∣ z - 1 ∣ - \frac{1}{5} ln ∣ z + 4 ∣) + ln ∣ x ∣

\frac{ln ( u ^{2} ) - ln ( u ) + ln ( u )}{ln ( u ^{3} )}

ln (\frac{x ^{4} + 1 - x ^{2}}{x ^{4} + 1 + x ^{2}})

lo g_{\frac{4}{3}} (- 3 x) + 6

What is 4log_{b}(v)+3log_{b}(q) ?
The solution to 4log_{b}(v)+3log_{b}(q) is log_{b}(v^4q^3)