What is 4log_{10}(x-1)-log_{10}(x+1) ?

The solution to 4log_{10}(x-1)-log_{10}(x+1) is log_{10}(((x-1)^4)/(x+1))

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simplify 4log_{10}(x-1)-log_{10}(x+1)

simplify

4 lo g_{10} (x - 1) - lo g_{10} (x + 1)

lo g_{10} (\frac{( x - 1 ) ^{4}}{x + 1})

Solution steps

4 lo g_{10} (x - 1) - lo g_{10} (x + 1)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{10} (x - 1) = lo g_{10} ((x - 1)^{4})

= lo g_{10} ((x - 1)^{4}) - lo g_{10} (x + 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} ((x - 1)^{4}) - lo g_{10} (x + 1) = lo g_{10} (\frac{( x - 1 ) ^{4}}{x + 1})

= lo g_{10} (\frac{( x - 1 ) ^{4}}{x + 1})

ln (\frac{97}{100})

2^{2 l n (x) + l n (y)}

3 lo g_{10} (x) + 4 lo g_{10} (y) - 6 lo g_{10} (z)

2 \cdot (ln (0.07) - ln (0.06))

ln (258) - ln (2)

What is 4log_{10}(x-1)-log_{10}(x+1) ?
The solution to 4log_{10}(x-1)-log_{10}(x+1) is log_{10}(((x-1)^4)/(x+1))