What are the solutions to the equation z^2-4=0 ?

The solutions to the equation z^2-4=0 are z=2,z=-2

Find the zeros of z^2-4=0

The zeros of z^2-4=0 are z=2,z=-2

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z^{2} - 4 = 0

z = 2, z = - 2

Solution steps

z^{2} - 4 = 0

Move

4

to the right side

z^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

z = 4, z = - 4

4 = 2

- 4 = - 2

z = 2, z = - 2

0^{\frac{1}{2}}

3 x + 7 > x + 3

9 - 6 x + 3 \geq 6

∣ 5 x - 15 ∣ \geq 20

\frac{1 0 ^{- 14}}{1.4 \cdot 1 0 ^{- 2}}

What are the solutions to the equation z^2-4=0 ?
The solutions to the equation z^2-4=0 are z=2,z=-2
Find the zeros of z^2-4=0
The zeros of z^2-4=0 are z=2,z=-2