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Popular >

simplify ln|x-1|-ln|x+1|

Solution

simplify

ln ∣ x - 1 ∣ - ln ∣ x + 1 ∣

Solution

ln (\frac{∣ x - 1 ∣}{∣ x + 1 ∣})

Solution steps

ln ∣ x - 1 ∣ - ln ∣ x + 1 ∣

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ∣ x - 1 ∣ - ln ∣ x + 1 ∣ = ln (\frac{∣ x - 1 ∣}{∣ x + 1 ∣})

= ln (\frac{∣ x - 1 ∣}{∣ x + 1 ∣})

Popular Examples

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simplify log_{10}(x+2)+2log_{10}(x-3)simplify

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expand log_{10}((k^3)/2)expand

lo g_{10} (\frac{k ^{3}}{2})

expand log_{10}((24m^2)/(16p))expand

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Frequently Asked Questions (FAQ)

What is ln|x-1|-ln|x+1| ?
The solution to ln|x-1|-ln|x+1| is ln((|x-1|)/(|x+1|))