What are the solutions to the equation m^2+21m-22=0 ?

The solutions to the equation m^2+21m-22=0 are m=1,m=-22

Find the zeros of m^2+21m-22=0

The zeros of m^2+21m-22=0 are m=1,m=-22

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m^{2} + 21 m - 22 = 0

m = 1, m = - 22

Solution steps

m^{2} + 21 m - 22 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 1 \cdot ( - 22 )}{2 \cdot 1}

2 1^{2} - 4 \cdot 1 \cdot (- 22) = 23

m_{1, 2} = \frac{- 21 \pm 23}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 21 + 23}{2 \cdot 1}, m_{2} = \frac{- 21 - 23}{2 \cdot 1}

m = \frac{- 21 + 23}{2 \cdot 1} : 1

m = \frac{- 21 - 23}{2 \cdot 1} : - 22

The solutions to the quadratic equation are:

m = 1, m = - 22

lo g_{4} (2) + lo g_{4} (32)

5 (y) (- y) (y^{2}) (- y^{2})

\frac{x}{9} + 16 = 20

\frac{5 + 3}{4 + 3}

6 x^{2} - 31 x - 30 = 0

What are the solutions to the equation m^2+21m-22=0 ?
The solutions to the equation m^2+21m-22=0 are m=1,m=-22
Find the zeros of m^2+21m-22=0
The zeros of m^2+21m-22=0 are m=1,m=-22