What is 1/(ln(x))+ln(1/x) ?

The solution to 1/(ln(x))+ln(1/x) is 1/(ln(x))++ln(1)-ln(x)

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simplify 1/(ln(x))+ln(1/x)

simplify

\frac{1}{ln ( x )} + ln (\frac{1}{x})

\frac{1}{ln ( x )} + + ln (1) - ln (x)

Solution steps

\frac{1}{ln ( x )} + ln (\frac{1}{x})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1}{x}) = ln (1) - ln (x)

= \frac{1}{ln ( x )} + + ln (1) - ln (x)

6 ln \frac{y}{x} - 1 - ln \frac{y}{x} + 4 + 5 ln ∣ x ∣

ln (\frac{x ^{4}}{e ^{3 y}})

3 ln (3) - 2 ln (5) - ln (7)

\frac{1}{2} ln (x + 5) - 2 ln (x) + ln (y)

- lo g_{e} (x) - lo g_{e} (y)

What is 1/(ln(x))+ln(1/x) ?
The solution to 1/(ln(x))+ln(1/x) is 1/(ln(x))++ln(1)-ln(x)