What is ln((1+x^2)/(1-x^2)) ?

The solution to ln((1+x^2)/(1-x^2)) is ln(1+x^2)-ln(1-x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln((1+x^2)/(1-x^2))

simplify

ln (\frac{1 + x ^{2}}{1 - x ^{2}})

ln (1 + x^{2}) - ln (1 - x^{2})

Solution steps

ln (\frac{1 + x ^{2}}{1 - x ^{2}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1 + x ^{2}}{1 - x ^{2}}) = ln (1 + x^{2}) - ln (1 - x^{2})

= ln (x^{2} + 1) - ln (- x^{2} + 1)

\frac{1}{180} (ln ∣ 180 x - 30 ∣ - ln (30))

- lo g_{10} (6 \cdot 1 0^{- 3})

3 ln (4) - \frac{1}{2} ln (x^{2} + 4)

ln (6 p) + 3 ln (2 p - 5) - ln (9)

2 lo g_{6} (x) + 5 lo g_{6} (y)

What is ln((1+x^2)/(1-x^2)) ?
The solution to ln((1+x^2)/(1-x^2)) is ln(1+x^2)-ln(1-x^2)