What is expand log_{2}(r^{1/3})t ?

The solution to expand log_{2}(r^{1/3})t is (tlog_{2}(r))/3

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expand log_{2}(r^{1/3})t

expand

lo g_{2} (r^{\frac{1}{3}}) t

\frac{t lo g _{2} ( r )}{3}

Solution steps

lo g_{2} (r^{\frac{1}{3}}) t

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{2} (r^{\frac{1}{3}}) = \frac{1}{3} lo g_{2} (r)

= \frac{1}{3} lo g_{2} (r) t

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot t}{3} lo g_{2} (r)

Multiply:

1 \cdot t = t

= \frac{t}{3} lo g_{2} (r)

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{t lo g _{2} ( r )}{3}

- lo g_{10} (1.9 \cdot 1 0^{- 3})

lo g_{5} (x^{5})

ln (\frac{1}{x ^{2} + y ^{2}})

\frac{8.314 \cdot 310}{1 \cdot 96485} ln (\frac{5.3}{140})

lo g_{10} (x + 2) - \frac{1}{2} lo g_{10} (1 + x^{2})

What is expand log_{2}(r^{1/3})t ?
The solution to expand log_{2}(r^{1/3})t is (tlog_{2}(r))/3