What is join log_{10}(2)-1/(2ln(10)) ?

The solution to join log_{10}(2)-1/(2ln(10)) is log_{10}(2)-1/(ln(100))

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join log_{10}(2)-1/(2ln(10))

join

lo g_{10} (2) - \frac{1}{2 ln ( 10 )}

lo g_{10} (2) - \frac{1}{ln ( 100 )}

Decimal Notation

0.08388 \dots

Solution steps

lo g_{10} (2) - \frac{1}{2 ln ( 10 )}

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 ln (10) = ln (1 0^{2})

= lo g_{10} (2) - \frac{1}{ln ( 1 0 ^{2} )}

1 0^{2} = 100

= lo g_{10} (2) - \frac{1}{ln ( 100 )}

6 ln (6) - 4 ln (4) - 2

ln (\frac{0.1}{0.9})

\frac{1}{2 a} (ln \frac{u}{a} + 1 - ln \frac{u}{a} - 1) + C

ln (x (y + 1))

ln (- \frac{4}{3}) - ln (- \frac{7}{6})

What is join log_{10}(2)-1/(2ln(10)) ?
The solution to join log_{10}(2)-1/(2ln(10)) is log_{10}(2)-1/(ln(100))