What are the solutions to the equation 64x^2-16x+1=0 ?

The solutions to the equation 64x^2-16x+1=0 are x= 1/8

Find the zeros of 64x^2-16x+1=0

The zeros of 64x^2-16x+1=0 are x= 1/8

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64 x^{2} - 16 x + 1 = 0

x = \frac{1}{8}

Solution steps

64 x^{2} - 16 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 64 \cdot 1}{2 \cdot 64}

(- 16)^{2} - 4 \cdot 64 \cdot 1 = 0

x_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 64}

x = \frac{- ( - 16 )}{2 \cdot 64}

\frac{- ( - 16 )}{2 \cdot 64} = \frac{1}{8}

x = \frac{1}{8}

The solution to the quadratic equation is:

x = \frac{1}{8}

x (ln (6^{- 1})) = ln (6)

10 y^{2} + 47 y + 9

(x - 2) (x - 1) = 6

26 + m \geq 5 (- 6 + 3 m)

\frac{2 π}{5} - \frac{3 π}{7}

What are the solutions to the equation 64x^2-16x+1=0 ?
The solutions to the equation 64x^2-16x+1=0 are x= 1/8
Find the zeros of 64x^2-16x+1=0
The zeros of 64x^2-16x+1=0 are x= 1/8