What are the solutions to the equation (x-2)(x-1)=6 ?

The solutions to the equation (x-2)(x-1)=6 are x=4,x=-1

Find the zeros of (x-2)(x-1)=6

The zeros of (x-2)(x-1)=6 are x=4,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x - 2) (x - 1) = 6

x = 4, x = - 1

Solution steps

(x - 2) (x - 1) = 6

Expand

(x - 2) (x - 1) : x^{2} - 3 x + 2

x^{2} - 3 x + 2 = 6

Move

6

to the left side

x^{2} - 3 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 4) = 5

x_{1, 2} = \frac{- ( - 3 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 5}{2 \cdot 1}

x = \frac{- ( - 3 ) + 5}{2 \cdot 1} : 4

x = \frac{- ( - 3 ) - 5}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 4, x = - 1

26 + m \geq 5 (- 6 + 3 m)

\frac{2 π}{5} - \frac{3 π}{7}

2 y - 4 = 10

∣ 4 x - 3 ∣ = 10

z^{4} + 2 z^{3} - 2 z^{2} + 8

What are the solutions to the equation (x-2)(x-1)=6 ?
The solutions to the equation (x-2)(x-1)=6 are x=4,x=-1
Find the zeros of (x-2)(x-1)=6
The zeros of (x-2)(x-1)=6 are x=4,x=-1