What is 1/2 ln|8.7+4|-1/2 ln|8.7+6|+C ?

The solution to 1/2 ln|8.7+4|-1/2 ln|8.7+6|+C is ln(0.92948…)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 1/2 ln|8.7+4|-1/2 ln|8.7+6|+C

simplify

\frac{1}{2} ln ∣ 8.7 + 4 ∣ - \frac{1}{2} ln ∣ 8.7 + 6 ∣ + C

ln (0.92948 \dots) + C

Solution steps

\frac{1}{2} ln ∣ 8.7 + 4 ∣ - \frac{1}{2} ln ∣ 8.7 + 6 ∣ + C

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

\frac{1}{2} ln ∣ 4 + 8.7 ∣ = ln (∣ 4 + 8.7 ∣^{\frac{1}{2}})

= ln (∣ 4 + 8.7 ∣^{\frac{1}{2}}) - \frac{1}{2} ln ∣ 6 + 8.7 ∣ + C

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

\frac{1}{2} ln ∣ 6 + 8.7 ∣ = ln (∣ 6 + 8.7 ∣^{\frac{1}{2}})

= ln (∣ 4 + 8.7 ∣^{\frac{1}{2}}) - ln (∣ 6 + 8.7 ∣^{\frac{1}{2}}) + C

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (∣ 8.7 + 4 ∣^{\frac{1}{2}}) - ln (∣ 8.7 + 6 ∣^{\frac{1}{2}}) = ln (\frac{∣ 4 + 8.7 ∣ ^{\frac{1}{2}}}{∣ 6 + 8.7 ∣ ^{\frac{1}{2}}})

= ln (\frac{∣ 4 + 8.7 ∣ ^{\frac{1}{2}}}{∣ 6 + 8.7 ∣ ^{\frac{1}{2}}}) + C

\frac{∣ 8.7 + 4 ∣ ^{\frac{1}{2}}}{∣ 8.7 + 6 ∣ ^{\frac{1}{2}}} = 0.92948 \dots

= ln (0.92948 \dots) + C

\frac{1}{4} \cdot ln (2)

ln (\frac{3}{e})

ln (t x)

lo g_{10} (\frac{a b ^{3}}{100 c})

\frac{1}{5} \cdot lo g_{7} (x) - \frac{1}{3} \cdot lo g_{7} (y)

What is 1/2 ln|8.7+4|-1/2 ln|8.7+6|+C ?
The solution to 1/2 ln|8.7+4|-1/2 ln|8.7+6|+C is ln(0.92948…)+C