What is ln(b)+(ln(c))/2-3ln(d) ?

The solution to ln(b)+(ln(c))/2-3ln(d) is ln(b/(d^3))+(ln(c))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ln(b)+(ln(c))/2-3ln(d)

simplify

ln (b) + \frac{ln ( c )}{2} - 3 ln (d)

ln (\frac{b}{d ^{3}}) + \frac{ln ( c )}{2}

Solution steps

ln (b) + \frac{ln ( c )}{2} - 3 ln (d)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 ln (d) = ln (d^{3})

= ln (b) + \frac{ln ( c )}{2} - ln (d^{3})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (b) - ln (d^{3}) = ln (\frac{b}{d ^{3}})

= ln (\frac{b}{d ^{3}}) + \frac{ln ( c )}{2}

ln (\frac{x - 3}{x + 3})

ln \frac{x}{2} + 1 + ln \frac{x}{2} - 1

2000 ln (\frac{5}{4})

2 ln (x y)

ln (3 y^{2})

What is ln(b)+(ln(c))/2-3ln(d) ?
The solution to ln(b)+(ln(c))/2-3ln(d) is ln(b/(d^3))+(ln(c))/2