What is (sqrt(|x+4|^2)-25)(sqrt(x^2-9))<= 0 ?

The solution to (sqrt(|x+4|^2)-25)(sqrt(x^2-9))<= 0 is -29<= x<=-3\lor 3<= x<= 21

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(sqrt(|x+4|^2)-25)(sqrt(x^2-9))<= 0

(∣ x + 4 ∣^{2} - 25) (x^{2} - 9) \leq 0

- 29 \leq x \leq - 3 or 3 \leq x \leq 21

Interval Notation

[- 29, - 3] \cup [3, 21]

Solution steps

(∣ x + 4 ∣^{2} - 25) x^{2} - 9 \leq 0

Identify the intervals

- 29 \leq x \leq - 3 or 3 \leq x \leq 21

- 120 (7) (\frac{4}{5}) - 120 (\frac{3}{5}) (3)

x^{2} - 1 x - 56

- (m - 6) = 3 m + 14

\frac{3}{7} (x - 2) = 15

∣ (3 x - 2) - 7 ∣ < \frac{1}{2}

What is (sqrt(|x+4|^2)-25)(sqrt(x^2-9))<= 0 ?
The solution to (sqrt(|x+4|^2)-25)(sqrt(x^2-9))<= 0 is -29<= x<=-3\lor 3<= x<= 21