What is 4[ln(x)-ln(x+9)-ln(x-9)] ?

The solution to 4[ln(x)-ln(x+9)-ln(x-9)] is 4ln(x/((x+9)(x-9)))

Popular >

simplify 4[ln(x)-ln(x+9)-ln(x-9)]

simplify

4 [ln (x) - ln (x + 9) - ln (x - 9)]

4 ln (\frac{x}{( x + 9 ) ( x - 9 )})

Solution steps

4 [ln (x) - ln (x + 9) - ln (x - 9)]

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (x) - ln (x + 9) = ln (\frac{x}{x + 9})

= 4 [ln (\frac{x}{x + 9}) - ln (x - 9)]

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (\frac{x}{x + 9}) - ln (x - 9) = ln (\frac{\frac{x}{x + 9}}{x - 9})

= 4 [ln (\frac{\frac{x}{x + 9}}{x - 9})]

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= 4 [ln (\frac{x}{( x + 9 ) ( x - 9 )})]

Remove parentheses:

(a) = a

= 4 ln (\frac{x}{( x + 9 ) ( x - 9 )})

ln (\frac{( x - 2 ) ^{5}}{( x + 1 ) ^{3}})

4 lo g_{10} (x) - \frac{1}{3} (x^{2} + 1) + 2 lo g_{10} (x - 1)

6 ln (\frac{5}{2}) - \frac{9}{5}

lo g_{9} (\frac{1}{6})

ln (\frac{821.85}{1643}) \cdot 8

What is 4[ln(x)-ln(x+9)-ln(x-9)] ?
The solution to 4[ln(x)-ln(x+9)-ln(x-9)] is 4ln(x/((x+9)(x-9)))