What is log_{1.025}(40/13)+4 ?

The solution to log_{1.025}(40/13)+4 is log_{1.025}(40)-log_{1.025}(13)+4

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simplify log_{1.025}(40/13)+4

simplify

lo g_{1.025} (\frac{40}{13}) + 4

lo g_{1.025} (40) - lo g_{1.025} (13) + 4

Decimal Notation

49.51685 \dots

Solution steps

lo g_{1.025} (\frac{40}{13}) + 4

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{1.025} (\frac{40}{13}) = lo g_{1.025} (40) - lo g_{1.025} (13)

= lo g_{1.025} (40) - lo g_{1.025} (13) + 4

2 ln (23)

\frac{1}{6} ln (2)

lo g_{10} (2 π \cdot 501.24 \cdot 0.98 \cdot 111.2 \cdot 1 0^{- 6})

\frac{ln ( 29 ) - ln ( 74 )}{- 0.0453}

ln (2) + 2 ln (x)

What is log_{1.025}(40/13)+4 ?
The solution to log_{1.025}(40/13)+4 is log_{1.025}(40)-log_{1.025}(13)+4