What is ln((n^2-n)/(n^2-n-2)) ?

The solution to ln((n^2-n)/(n^2-n-2)) is ln(n^2-n)-ln(n^2-n-2)

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simplify ln((n^2-n)/(n^2-n-2))

simplify

ln (\frac{n ^{2} - n}{n ^{2} - n - 2})

ln (n^{2} - n) - ln (n^{2} - n - 2)

Solution steps

ln (\frac{n ^{2} - n}{n ^{2} - n - 2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{n ^{2} - n}{n ^{2} - n - 2}) = ln (n^{2} - n) - ln (n^{2} - n - 2)

= ln (n^{2} - n) - ln (n^{2} - n - 2)

- lo g_{10} (5 \cdot 1 0^{- 12})

3 ln (2) + ln (3)

lo g_{10} (\frac{x ^{4}}{y ^{2}})

ln (4) + 3 ln (3) - ln (12)

\frac{1}{10} \cdot ln (\frac{20}{60})

What is ln((n^2-n)/(n^2-n-2)) ?
The solution to ln((n^2-n)/(n^2-n-2)) is ln(n^2-n)-ln(n^2-n-2)