What are the solutions to the equation -2p^2+4000p=0 ?

The solutions to the equation -2p^2+4000p=0 are p=0,p=2000

Find the zeros of -2p^2+4000p=0

The zeros of -2p^2+4000p=0 are p=0,p=2000

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- 2 p^{2} + 4000 p = 0

p = 0, p = 2000

Solution steps

- 2 p^{2} + 4000 p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 4000 \pm 400 0 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

400 0^{2} - 4 (- 2) \cdot 0 = 4000

p_{1, 2} = \frac{- 4000 \pm 4000}{2 ( - 2 )}

Separate the solutions

p_{1} = \frac{- 4000 + 4000}{2 ( - 2 )}, p_{2} = \frac{- 4000 - 4000}{2 ( - 2 )}

p = \frac{- 4000 + 4000}{2 ( - 2 )} : 0

p = \frac{- 4000 - 4000}{2 ( - 2 )} : 2000

The solutions to the quadratic equation are:

p = 0, p = 2000

3 x - 5 \geq 16

4 x^{2} + 8 x + 16

4 x^{2} - 15 x - 25 = 0

9 x + 10 = 7 x

\frac{125 - 7}{35 - 5}

What are the solutions to the equation -2p^2+4000p=0 ?
The solutions to the equation -2p^2+4000p=0 are p=0,p=2000
Find the zeros of -2p^2+4000p=0
The zeros of -2p^2+4000p=0 are p=0,p=2000