What is log_{e}(3x+1)+log_{e}(2) ?

The solution to log_{e}(3x+1)+log_{e}(2) is ln(2(3x+1))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{e}(3x+1)+log_{e}(2)

simplify

lo g_{e} (3 x + 1) + lo g_{e} (2)

ln (2 (3 x + 1))

Solution steps

lo g_{e} (3 x + 1) + lo g_{e} (2)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{e} (3 x + 1) + lo g_{e} (2) = lo g_{e} (2 (3 x + 1))

= lo g_{e} ((3 x + 1) \cdot 2)

Apply log rule:

lo g_{e} (x) = ln (x)

= ln (2 (3 x + 1))

\frac{1}{10} ln (10)

2 ln (53)

(100000 \cdot 0.25) \cdot ln (\frac{0.1}{0.25})

- lo g_{10} (5.8 \cdot 1 0^{- 10})

\frac{1}{2} lo g_{10} (x) - 3 lo g_{10} (y)

What is log_{e}(3x+1)+log_{e}(2) ?
The solution to log_{e}(3x+1)+log_{e}(2) is ln(2(3x+1))