What is join (81ln^4(2))/4-4ln^4(2) ?

The solution to join (81ln^4(2))/4-4ln^4(2) is (ln^4(2^{81}))/4-4ln^4(2)

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join (81ln^4(2))/4-4ln^4(2)

join

\frac{81 ln ^{4} ( 2 )}{4} - 4 ln^{4} (2)

\frac{ln ^{4} ( 2 ^{81} )}{4} - 4 ln^{4} (2)

Decimal Notation

2484172.59808 \dots

Solution steps

\frac{81 ln ^{4} ( 2 )}{4} - 4 ln^{4} (2)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

81 ln^{4} (2) = ln^{4} (2^{81})

= \frac{ln ^{4} ( 2 ^{81} )}{4} - 4 ln^{4} (2)

4 lo g_{10} (m) + lo g_{10} (n)

- \frac{1}{3} ln (z) + \frac{2}{5} ln (y) - ln (x) + ln (2)

\frac{1}{2} lo g_{b} (x) - 2 lo g_{b} (y) + lo g_{b} (z)

ln (\frac{- 28}{242})

\frac{1}{4} ln ∣ 6 - 2 ∣ - \frac{1}{4} ln ∣ 6 + 2 ∣

What is join (81ln^4(2))/4-4ln^4(2) ?
The solution to join (81ln^4(2))/4-4ln^4(2) is (ln^4(2^{81}))/4-4ln^4(2)