What are the solutions to the equation x^2+14x+43=0 ?

The solutions to the equation x^2+14x+43=0 are x=-7+sqrt(6),x=-7-sqrt(6)

Find the zeros of x^2+14x+43=0

The zeros of x^2+14x+43=0 are x=-7+sqrt(6),x=-7-sqrt(6)

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x^{2} + 14 x + 43 = 0

x = - 7 + 6, x = - 7 - 6

Solution steps

x^{2} + 14 x + 43 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot 43}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot 43 = 26

x_{1, 2} = \frac{- 14 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 14 - 2 6}{2 \cdot 1}

x = \frac{- 14 + 2 6}{2 \cdot 1} : - 7 + 6

x = \frac{- 14 - 2 6}{2 \cdot 1} : - 7 - 6

The solutions to the quadratic equation are:

x = - 7 + 6, x = - 7 - 6

3 x^{2} + 2 x + 8 = 0

(4 x + 2)^{2}

31

8 c - 6 \leq - 5 c - 3

x^{2} y^{2} - 64

What are the solutions to the equation x^2+14x+43=0 ?
The solutions to the equation x^2+14x+43=0 are x=-7+sqrt(6),x=-7-sqrt(6)
Find the zeros of x^2+14x+43=0
The zeros of x^2+14x+43=0 are x=-7+sqrt(6),x=-7-sqrt(6)