What are the solutions to the equation (x-2)(x-4)=0 ?

The solutions to the equation (x-2)(x-4)=0 are x=2,x=4

Find the zeros of (x-2)(x-4)=0

The zeros of (x-2)(x-4)=0 are x=2,x=4

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(x - 2) (x - 4) = 0

x = 2, x = 4

Solution steps

(x - 2) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or x - 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = 2, x = 4

8 x^{5} y^{3} + 32 x^{2} y^{8} - 64 x^{4} y^{2}

x (x + 2) = 5 (x + x + 2) - 1

π \cdot 3^{2}

3 - 2 x = 7 + 3 x

∣ x - 4 ∣ < 7

What are the solutions to the equation (x-2)(x-4)=0 ?
The solutions to the equation (x-2)(x-4)=0 are x=2,x=4
Find the zeros of (x-2)(x-4)=0
The zeros of (x-2)(x-4)=0 are x=2,x=4