What are the solutions to the equation 460=(15+2x)(12+2x) ?

The solutions to the equation 460=(15+2x)(12+2x) are x=4,x=-35/2

Find the zeros of 460=(15+2x)(12+2x)

The zeros of 460=(15+2x)(12+2x) are x=4,x=-35/2

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460 = (15 + 2 x) (12 + 2 x)

x = 4, x = - \frac{35}{2}

Decimal Notation

x = 4, x = - 17.5

Solution steps

460 = (15 + 2 x) (12 + 2 x)

Expand

(15 + 2 x) (12 + 2 x) : 180 + 54 x + 4 x^{2}

460 = 180 + 54 x + 4 x^{2}

Switch sides

180 + 54 x + 4 x^{2} = 460

Move

460

to the left side

4 x^{2} + 54 x - 280 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 54 \pm 5 4 ^{2} - 4 \cdot 4 ( - 280 )}{2 \cdot 4}

5 4^{2} - 4 \cdot 4 (- 280) = 86

x_{1, 2} = \frac{- 54 \pm 86}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 54 + 86}{2 \cdot 4}, x_{2} = \frac{- 54 - 86}{2 \cdot 4}

x = \frac{- 54 + 86}{2 \cdot 4} : 4

x = \frac{- 54 - 86}{2 \cdot 4} : - \frac{35}{2}

The solutions to the quadratic equation are:

x = 4, x = - \frac{35}{2}

∣ m + 5 ∣ + 9 = 16

- 5 y^{2} = 1.8

\frac{h}{5} = 5.1

18 = \frac{2}{5} f

\frac{36}{( 0.8 \cdot 3 \cdot 1 0 ^{8} )}

What are the solutions to the equation 460=(15+2x)(12+2x) ?
The solutions to the equation 460=(15+2x)(12+2x) are x=4,x=-35/2
Find the zeros of 460=(15+2x)(12+2x)
The zeros of 460=(15+2x)(12+2x) are x=4,x=-35/2