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Popular >

simplify log_{7}(e^x2^x)

Solution

simplify

lo g_{7} (e^{x} 2^{x})

Solution

x lo g_{7} (e) + x lo g_{7} (2)

Solution steps

lo g_{7} (e^{x} \cdot 2^{x})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{7} (e^{x} \cdot 2^{x}) = lo g_{7} (e^{x}) + lo g_{7} (2^{x})

= lo g_{7} (e^{x}) + lo g_{7} (2^{x})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{7} (e^{x}) = x lo g_{7} (e)

= x lo g_{7} (e) + lo g_{7} (2^{x})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{7} (2^{x}) = x lo g_{7} (2)

= x lo g_{7} (e) + x lo g_{7} (2)

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Frequently Asked Questions (FAQ)

What is log_{7}(e^x2^x) ?
The solution to log_{7}(e^x2^x) is xlog_{7}(e)+xlog_{7}(2)