What is log_{10}(42.61)-log_{10}(26.03) ?

The solution to log_{10}(42.61)-log_{10}(26.03) is log_{10}(4261/2603)

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simplify log_{10}(42.61)-log_{10}(26.03)

simplify

lo g_{10} (42.61) - lo g_{10} (26.03)

lo g_{10} (\frac{4261}{2603})

Decimal Notation

0.21403 \dots

Solution steps

lo g_{10} (42.61) - lo g_{10} (26.03)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (42.61) - lo g_{10} (26.03) = lo g_{10} (\frac{42.61}{26.03})

= lo g_{10} (\frac{42.61}{26.03})

\frac{42.61}{26.03} = \frac{4261}{2603}

= lo g_{10} (\frac{4261}{2603})

- lo g_{10} (4.25 \cdot 1 0^{- 7})

2 lo g_{2} (x) + lo g_{2} (y)

\frac{1}{32} ln (x + 2) - \frac{1}{32} ln (x - 2)

lo g_{9} ((\frac{8 ^{5}}{11})^{4})

4 lo g_{5} (x) - 6 lo g_{5} (y)

What is log_{10}(42.61)-log_{10}(26.03) ?
The solution to log_{10}(42.61)-log_{10}(26.03) is log_{10}(4261/2603)