What is log_{15}((17-4x)/2)+e^{x^2-x-2} ?

The solution to log_{15}((17-4x)/2)+e^{x^2-x-2} is log_{15}(17-4x)-log_{15}(2)+e^{x^2-x-2}

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simplify log_{15}((17-4x)/2)+e^{x^2-x-2}

simplify

lo g_{15} (\frac{17 - 4 x}{2}) + e^{x^{2} - x - 2}

lo g_{15} (17 - 4 x) - lo g_{15} (2) + e^{x^{2} - x - 2}

Solution steps

lo g_{15} (\frac{17 - 4 x}{2}) + e^{x^{2} - x - 2}

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{15} (\frac{17 - 4 x}{2}) = lo g_{15} (17 - 4 x) - lo g_{15} (2)

= lo g_{15} (- 4 x + 17) - lo g_{15} (2) + e^{x^{2} - x - 2}

ln (2 e^{3 x})

- lo g_{10} (2 \cdot 1 0^{- 12})

ln ((θ + 1) x^{θ})

- lo g_{10} (8.1 \cdot 1 0^{- 6})

\frac{ln ( \frac{3025}{81} ) - 16 ln ( 2 )}{ln ( 2 )}

What is log_{15}((17-4x)/2)+e^{x^2-x-2} ?
The solution to log_{15}((17-4x)/2)+e^{x^2-x-2} is log_{15}(17-4x)-log_{15}(2)+e^{x^2-x-2}