What is (3/(ln(7)-ln(4)))/(3x+4) ?

The solution to (3/(ln(7)-ln(4)))/(3x+4) is 3/(ln(7/4)(3x+4))

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simplify (3/(ln(7)-ln(4)))/(3x+4)

simplify

\frac{\frac{3}{l n ( 7 ) - l n ( 4 )}}{3 x + 4}

\frac{3}{ln ( \frac{7}{4} ) ( 3 x + 4 )}

Solution steps

\frac{\frac{3}{l n ( 7 ) - l n ( 4 )}}{3 x + 4}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (7) - ln (4) = ln (\frac{7}{4})

= \frac{\frac{3}{l n ( \frac{7}{4} )}}{3 x + 4}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3}{ln ( \frac{7}{4} ) ( 3 x + 4 )}

- lo g_{10} (7.1 \cdot 1 0^{- 7})

5 ln (2) + 3 ln (x) - \frac{1}{2} ln (x + 9)

- \frac{ln ( 0.965 ) - ln ( \frac{190}{749} )}{0.01 ln ( 0.965 )}

ln (sin (x)) + ln (cos (x))

ln (\frac{7 y - 6}{y})

What is (3/(ln(7)-ln(4)))/(3x+4) ?
The solution to (3/(ln(7)-ln(4)))/(3x+4) is 3/(ln(7/4)(3x+4))