What is (ln(2.98)-ln(3))/((2.98)-3) ?

The solution to (ln(2.98)-ln(3))/((2.98)-3) is -(ln(0.99333…))/(0.02)

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simplify (ln(2.98)-ln(3))/((2.98)-3)

simplify

\frac{ln ( 2.98 ) - ln ( 3 )}{( 2.98 ) - 3}

- \frac{ln ( 0.99333 \dots )}{0.02}

Decimal Notation

0.33444 \dots

Solution steps

\frac{ln ( 2.98 ) - ln ( 3 )}{( 2.98 ) - 3}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (2.98) - ln (3) = ln (\frac{2.98}{3})

= \frac{ln ( \frac{2.98}{3} )}{2.98 - 3}

Divide the numbers:

\frac{2.98}{3} = 0.99333 \dots

= \frac{ln ( 0.99333 \dots )}{2.98 - 3}

Subtract the numbers:

2.98 - 3 = - 0.02

= \frac{ln ( 0.99333 \dots )}{- 0.02}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{ln ( 0.99333 \dots )}{0.02}

\frac{3}{2} (\frac{2 ln ( 2 ) + 2 ln ( \frac{7}{2} )}{2})

ln ∣ z + 4 ∣ + \frac{6}{5} ln (\frac{∣ z - 1 ∣}{∣ z + 4 ∣}) + ln ∣ x ∣

\frac{ln ( 50000000 ) - ln ( 80000000 )}{7 - 4}

- lo g_{10} (2.73 \cdot 1 0^{- 6})

ln (\frac{1.25}{2 \cdot 0.085})

What is (ln(2.98)-ln(3))/((2.98)-3) ?
The solution to (ln(2.98)-ln(3))/((2.98)-3) is -(ln(0.99333…))/(0.02)