What are the solutions to the equation 9x^2+x-2=0 ?

The solutions to the equation 9x^2+x-2=0 are x=(-1+sqrt(73))/(18),x=(-1-sqrt(73))/(18)

Find the zeros of 9x^2+x-2=0

The zeros of 9x^2+x-2=0 are x=(-1+sqrt(73))/(18),x=(-1-sqrt(73))/(18)

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9 x^{2} + x - 2 = 0

x = \frac{- 1 + 73}{18}, x = \frac{- 1 - 73}{18}

Decimal Notation

x = 0.41911 \dots, x = - 0.53022 \dots

Solution steps

9 x^{2} + x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 9 ( - 2 )}{2 \cdot 9}

1^{2} - 4 \cdot 9 (- 2) = 73

x_{1, 2} = \frac{- 1 \pm 73}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 1 + 73}{2 \cdot 9}, x_{2} = \frac{- 1 - 73}{2 \cdot 9}

x = \frac{- 1 + 73}{2 \cdot 9} : \frac{- 1 + 73}{18}

x = \frac{- 1 - 73}{2 \cdot 9} : \frac{- 1 - 73}{18}

The solutions to the quadratic equation are:

x = \frac{- 1 + 73}{18}, x = \frac{- 1 - 73}{18}

12 b^{2} - 52 b - 9 = 0

\frac{x}{2} + \frac{3}{5} = \frac{4}{3} - \frac{x}{6}

\frac{1}{3} + \frac{2}{6}

8 y = 12 y^{2}

\frac{125}{20}

What are the solutions to the equation 9x^2+x-2=0 ?
The solutions to the equation 9x^2+x-2=0 are x=(-1+sqrt(73))/(18),x=(-1-sqrt(73))/(18)
Find the zeros of 9x^2+x-2=0
The zeros of 9x^2+x-2=0 are x=(-1+sqrt(73))/(18),x=(-1-sqrt(73))/(18)