What is expand log_{12}((x-7)/(x+2)) ?

The solution to expand log_{12}((x-7)/(x+2)) is log_{12}(x-7)-log_{12}(x+2)

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expand log_{12}((x-7)/(x+2))

expand

lo g_{12} (\frac{x - 7}{x + 2})

lo g_{12} (x - 7) - lo g_{12} (x + 2)

Solution steps

lo g_{12} (\frac{x - 7}{x + 2})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{12} (\frac{x - 7}{x + 2}) = lo g_{12} (x - 7) - lo g_{12} (x + 2)

= lo g_{12} (x - 7) - lo g_{12} (x + 2)

ln (10) - 2 ln (3)

1.8 \cdot ln (\frac{2.2 - 5.1}{- 3.1})

4 ln (\frac{1}{3}) - 6 ln (\frac{1}{9})

4 ln (a) - 2 ln (b)

ln (20) - ln (4)

What is expand log_{12}((x-7)/(x+2)) ?
The solution to expand log_{12}((x-7)/(x+2)) is log_{12}(x-7)-log_{12}(x+2)