What are the solutions to the equation 3x(x-1)=-17x^2+2 ?

The solutions to the equation 3x(x-1)=-17x^2+2 are x= 2/5 ,x=-1/4

Find the zeros of 3x(x-1)=-17x^2+2

The zeros of 3x(x-1)=-17x^2+2 are x= 2/5 ,x=-1/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x (x - 1) = - 17 x^{2} + 2

x = \frac{2}{5}, x = - \frac{1}{4}

Decimal Notation

x = 0.4, x = - 0.25

Solution steps

3 x (x - 1) = - 17 x^{2} + 2

Expand

3 x (x - 1) : 3 x^{2} - 3 x

3 x^{2} - 3 x = - 17 x^{2} + 2

Move

2

to the left side

3 x^{2} - 3 x - 2 = - 17 x^{2}

Move

17 x^{2}

to the left side

20 x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 20 ( - 2 )}{2 \cdot 20}

(- 3)^{2} - 4 \cdot 20 (- 2) = 13

x_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 20}, x_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 20}

x = \frac{- ( - 3 ) + 13}{2 \cdot 20} : \frac{2}{5}

x = \frac{- ( - 3 ) - 13}{2 \cdot 20} : - \frac{1}{4}

The solutions to the quadratic equation are:

x = \frac{2}{5}, x = - \frac{1}{4}

x^{2} \leq 2 x + 48

4 s^{2} - s + 12 s t - 3 t

∣ 4 x - 7 ∣ - 5 \geq 1

180 - (2 x + 6) = 80

(\frac{2 x ^{5} y ^{8}}{5 x ^{6} y ^{5}})^{2}

What are the solutions to the equation 3x(x-1)=-17x^2+2 ?
The solutions to the equation 3x(x-1)=-17x^2+2 are x= 2/5 ,x=-1/4
Find the zeros of 3x(x-1)=-17x^2+2
The zeros of 3x(x-1)=-17x^2+2 are x= 2/5 ,x=-1/4