What is expand log_{5}((25x)^2) ?

The solution to expand log_{5}((25x)^2) is 4+2log_{5}(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand log_{5}((25x)^2)

expand

lo g_{5} ((25 x)^{2})

4 + 2 lo g_{5} (x)

Solution steps

lo g_{5} ((25 x)^{2})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{5} ((25 x)^{2}) = 2 lo g_{5} (25 x)

= 2 lo g_{5} (25 x)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

2 lo g_{5} (25 x) = 2 lo g_{5} (25) + 2 lo g_{5} (x)

= 2 lo g_{5} (25) + 2 lo g_{5} (x)

2 lo g_{5} (25) = 4

= 4 + 2 lo g_{5} (x)

ln (4 x^{2} y)

lo g_{10} (x) + \frac{1}{6} lo g_{10} (y)

- 0.2 lo g_{2} (0.2) - 0.8 lo g_{2} (0.8)

ln (4 \cdot cos (x))

3156659.5 \cdot ln (\frac{6.8}{1.2})

What is expand log_{5}((25x)^2) ?
The solution to expand log_{5}((25x)^2) is 4+2log_{5}(x)