What is 2log_{10}(9x)-log_{8}(2x-5) ?

The solution to 2log_{10}(9x)-log_{8}(2x-5) is 4log_{10}(3)+2log_{10}(x)-log_{8}(2x-5)

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simplify 2log_{10}(9x)-log_{8}(2x-5)

simplify

2 lo g_{10} (9 x) - lo g_{8} (2 x - 5)

4 lo g_{10} (3) + 2 lo g_{10} (x) - lo g_{8} (2 x - 5)

Solution steps

2 lo g_{10} (9 x) - lo g_{8} (2 x - 5)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

2 lo g_{10} (9 x) = 2 lo g_{10} (9) + 2 lo g_{10} (x)

= 2 lo g_{10} (9) + 2 lo g_{10} (x) - lo g_{8} (2 x - 5)

2 lo g_{10} (9) = 4 lo g_{10} (3)

= 4 lo g_{10} (3) + 2 lo g_{10} (x) - lo g_{8} (2 x - 5)

ln (\frac{0.05}{0.1})

\frac{3 ln ( 2 )}{ln ( \frac{27}{4} )}

ln (\frac{x - \frac{1}{2}}{x})

ln (\frac{2}{3})

ln (\frac{x ^{4} + c}{x ^{3}})

What is 2log_{10}(9x)-log_{8}(2x-5) ?
The solution to 2log_{10}(9x)-log_{8}(2x-5) is 4log_{10}(3)+2log_{10}(x)-log_{8}(2x-5)