What is (6*0.45)/(6-θ)+ln((1*0.55)/(1-θ)) ?

The solution to (6*0.45)/(6-θ)+ln((1*0.55)/(1-θ)) is (6*0.45)/(6-θ)++ln(1)+ln(0.55)-ln(1-θ)

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simplify (60.45)/(6-θ)+ln((10.55)/(1-θ))

simplify

\frac{6 \cdot 0.45}{6 - θ} + ln (\frac{1 \cdot 0.55}{1 - θ})

\frac{6 \cdot 0.45}{6 - θ} + + ln (1) + ln (0.55) - ln (1 - θ)

Solution steps

\frac{6 \cdot 0.45}{6 - θ} + ln (\frac{1 \cdot 0.55}{1 - θ})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{1 \cdot 0.55}{1 - θ}) = ln (1 \cdot 0.55) - ln (1 - θ)

= \frac{6 \cdot 0.45}{- θ + 6} + + ln (1 \cdot 0.55) - ln (- θ + 1)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (1 \cdot 0.55) = ln (1) + ln (0.55)

= \frac{6 \cdot 0.45}{- θ + 6} + + ln (1) + ln (0.55) - ln (- θ + 1)

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What is (6*0.45)/(6-θ)+ln((1*0.55)/(1-θ)) ?
The solution to (6*0.45)/(6-θ)+ln((1*0.55)/(1-θ)) is (6*0.45)/(6-θ)++ln(1)+ln(0.55)-ln(1-θ)