What is simplify-ln|u+1|+ln|u-1|+C ?

The solution to simplify-ln|u+1|+ln|u-1|+C is ln((|u-1|)/(|u+1|))+C

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simplify-ln|u+1|+ln|u-1|+C

simplify

- ln ∣ u + 1 ∣ + ln ∣ u - 1 ∣ + C

ln (\frac{∣ u - 1 ∣}{∣ u + 1 ∣}) + C

Solution steps

- ln ∣ u + 1 ∣ + ln ∣ u - 1 ∣ + C

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln ∣ u - 1 ∣ - ln ∣ u + 1 ∣ = ln (\frac{∣ u - 1 ∣}{∣ u + 1 ∣})

= ln (\frac{∣ u - 1 ∣}{∣ u + 1 ∣}) + C

ln (\frac{35 + 100}{738 + 100})

10 \cdot lo g_{10} (3.0057 \cdot 1 0^{- 13}) + 30

ln (x^{2}) + ln (z)

f (x) = ln ∣ x ∣ - \frac{1}{2} ln x^{2} + 1

\frac{1}{2} ln (3) - ln (2) - ln (\frac{1}{2})

What is simplify-ln|u+1|+ln|u-1|+C ?
The solution to simplify-ln|u+1|+ln|u-1|+C is ln((|u-1|)/(|u+1|))+C