What is 104-10*log_{10}((4*3.14*39^2)/2) ?

The solution to 104-10*log_{10}((4*3.14*39^2)/2) is 124-10log_{10}(955188)

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simplify 104-10log_{10}((43.14*39^2)/2)

simplify

104 - 10 \cdot lo g_{10} (\frac{4 \cdot 3.14 \cdot 3 9 ^{2}}{2})

124 - 10 lo g_{10} (955188)

Decimal Notation

64.19911 \dots

Solution steps

104 - 10 lo g_{10} (\frac{4 \cdot 3.14 \cdot 3 9 ^{2}}{2})

10 lo g_{10} (\frac{4 \cdot 3.14 \cdot 3 9 ^{2}}{2}) = 10 lo g_{10} (955188) - 20

= 104 - (10 lo g_{10} (955188) - 20)

Expand

- (10 lo g_{10} (955188) - 20) : - 10 lo g_{10} (955188) + 20

= 104 - 10 lo g_{10} (955188) + 20

Add the numbers:

104 + 20 = 124

= 124 - 10 lo g_{10} (955188)

1.56 - \frac{8.314 \cdot 298.15}{2 \cdot 96485} \cdot ln (\frac{1}{0.5})

1.05 ln (\frac{700}{1450}) + 0.287 ln (\frac{50}{2}) + \frac{50}{573}

ln (\frac{e ^{x}}{e ^{x} - 1})

\frac{5}{2} ln (x) + \frac{7}{2} ln (y) - ln (z) - 4 ln (z)

\frac{1}{3} ln ∣ x - 1 ∣ - \frac{1}{3} ln (x^{2} + x + 1)

What is 104-10*log_{10}((4*3.14*39^2)/2) ?
The solution to 104-10*log_{10}((4*3.14*39^2)/2) is 124-10log_{10}(955188)