What is 10log_{10}(9.64)-10log_{10}(0.37) ?

The solution to 10log_{10}(9.64)-10log_{10}(0.37) is log_{10}(1.4413E14)

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simplify 10log_{10}(9.64)-10log_{10}(0.37)

simplify

10 lo g_{10} (9.64) - 10 lo g_{10} (0.37)

lo g_{10} (1.4413 E 14)

Decimal Notation

14.15875 \dots

Solution steps

10 lo g_{10} (9.64) - 10 lo g_{10} (0.37)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

10 lo g_{10} (9.64) = lo g_{10} (9.6 4^{10})

= lo g_{10} (9.6 4^{10}) - 10 lo g_{10} (0.37)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

10 lo g_{10} (0.37) = lo g_{10} (0.3 7^{10})

= lo g_{10} (9.6 4^{10}) - lo g_{10} (0.3 7^{10})

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (9.6 4^{10}) - lo g_{10} (0.3 7^{10}) = lo g_{10} (\frac{9.6 4 ^{10}}{0.3 7 ^{10}})

= lo g_{10} (\frac{9.6 4 ^{10}}{0.3 7 ^{10}})

\frac{9.6 4 ^{10}}{0.3 7 ^{10}} = 1.4413 E 14

= lo g_{10} (1.4413 E 14)

\frac{1}{2} ln (\frac{7 + 7}{3})

8 lo g_{2} (x) - \frac{1}{4} \cdot lo g_{2} (y)

ln (\frac{u - 1}{u + 1})

2 ln (2) + 2 ln (3)

- 3 ln (3) + 6 ln (2)

What is 10log_{10}(9.64)-10log_{10}(0.37) ?
The solution to 10log_{10}(9.64)-10log_{10}(0.37) is log_{10}(1.4413E14)