What is ((ln(-cos(2))-ln(-cos(4)))acro)/2 ?

The solution to ((ln(-cos(2))-ln(-cos(4)))acro)/2 is (ln((cos(2))/(cos(4)))acro)/2

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simplify ((ln(-cos(2))-ln(-cos(4)))acro)/2

simplify

\frac{( ln ( - cos ( 2 ) ) - ln ( - cos ( 4 ) ) ) a cro}{2}

\frac{ln ( \frac{c o s ( 2 )}{c o s ( 4 )} ) a cro}{2}

Solution steps

\frac{( ln ( - cos ( 2 ) ) - ln ( - cos ( 4 ) ) ) a cro}{2}

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (- cos (2)) - ln (- cos (4)) = ln (\frac{- cos ( 2 )}{- cos ( 4 )})

= \frac{ln ( \frac{- c o s ( 2 )}{- c o s ( 4 )} ) a cro}{2}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{ln ( \frac{c o s ( 2 )}{c o s ( 4 )} ) a cro}{2}

ln (\frac{47}{50})

\frac{π}{8} ln (3)

2 ln (x) - ln (x - 1) + ln (x + 1)

- 0.7 \cdot lo g_{2} (0.7) - 0.3 lo g_{2} (0.3)

What is ((ln(-cos(2))-ln(-cos(4)))acro)/2 ?
The solution to ((ln(-cos(2))-ln(-cos(4)))acro)/2 is (ln((cos(2))/(cos(4)))acro)/2