What are the solutions to the equation x^2-2x+48=0 ?

The solutions to the equation x^2-2x+48=0 are x=1+sqrt(47)i,x=1-sqrt(47)i

Find the zeros of x^2-2x+48=0

The zeros of x^2-2x+48=0 are x=1+sqrt(47)i,x=1-sqrt(47)i

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x^{2} - 2 x + 48 = 0

x = 1 + 47 i, x = 1 - 47 i

Solution steps

x^{2} - 2 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 48}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 48 : 247 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 47 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 47 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 47 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 47 i}{2 \cdot 1} : 1 + 47 i

x = \frac{- ( - 2 ) - 2 47 i}{2 \cdot 1} : 1 - 47 i

The solutions to the quadratic equation are:

x = 1 + 47 i, x = 1 - 47 i

4 (3 x - 6)^{2} - 32

1 - \frac{4}{5} \times \frac{4}{5} \times \frac{4}{5}

9 x^{2} - 5 = 0

\frac{3 x}{7} + 6 = - 1 + \frac{4 x}{7}

\frac{16}{100}

What are the solutions to the equation x^2-2x+48=0 ?
The solutions to the equation x^2-2x+48=0 are x=1+sqrt(47)i,x=1-sqrt(47)i
Find the zeros of x^2-2x+48=0
The zeros of x^2-2x+48=0 are x=1+sqrt(47)i,x=1-sqrt(47)i